Question

(1+4x^2)y'=1 How do I differentiate this equation using separation of variables. I kind of just need some help ironing out my abilities.

Answer 1

I'm thinking first step is dividing by (1+4x^2) to separate
the variables??

Answer 2

separate variables:
\((1+4x^2){dy \over dx} =1\)
\(dy=\frac{dx}{1+4x^2}\)
now integrate

Answer 3

So that would make it y=arctan(2x)/2 ?

Answer 4

Seems like it :)
Don't forget the constant

Answer 5

oh shoot yeah... thanks!