Question

fThe equation of a circle is (x + 6)2 + (y - 4)2 = 16. The point (-6, 8) is on the circle.

What is the equation of the line that is tangent to the circle at (-6, 8)?

y= 8
x= 8
x= -2
y= 0

Answer 1

can you finish now?

Answer 2

I already had the aswer but thank you

Answer 3

If you're supposed to take a more calculus-oriented approach, you would do some implicit differentiation. Find \(dy/dx\) when \(x=-6\).

Answer 4

... and use that to find the equation of the tangent line.