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Mathematics 15 Online
OpenStudy (anonymous):

Help am I right. Please explain to me how to do this?

OpenStudy (anonymous):

OpenStudy (amistre64):

i take it your trying to work a triangle?

OpenStudy (amistre64):

first thing to do is draw a triangle .... and label it up

OpenStudy (amistre64):

|dw:1364316468013:dw|

OpenStudy (amistre64):

then put in what you know ....|dw:1364316504487:dw|

OpenStudy (amistre64):

now you would need to rummage thru your thoughts to see if you have anything that you can use to determine the other values of the triangle

OpenStudy (amistre64):

what do we know about the sum of all the angles of a triangle? dont they add up to something specific?

OpenStudy (anonymous):

Okay I did 15 sin 62 degrees = b Sin 73 degrees? Now what?

OpenStudy (amistre64):

first off, i wouldnt use 73 degrees for that

OpenStudy (amistre64):

but other than that, just divide off the sin 79 to determine a value for b

OpenStudy (amistre64):

\[\frac{b}{sinB}=\frac{a}{sinA}\] \[\frac{b~sinA}{sinB}=a\]is what i would try out since you seem to be wanting to apply the law of sines

OpenStudy (anonymous):

opps one sec.

OpenStudy (anonymous):

a = 10.72? @amistre64

OpenStudy (amistre64):

.... not quite. \[a=\frac{15sin(62^o)}{sin(39^o)}=abt~21.045^o\]

OpenStudy (amistre64):

lol .... thats not spose to be a degree on the end :) 21.045 in length

OpenStudy (anonymous):

a = 21.045

OpenStudy (amistre64):

thats what my calculator gives me, yes

OpenStudy (anonymous):

alright then how would I find c?

OpenStudy (amistre64):

|dw:1364317211812:dw|

OpenStudy (amistre64):

law of sines works .... so lets keep on using it \[\frac{c}{sinC}=\frac{b}{sinB}\] \[c=\frac{b~sinC}{sinB}\]

OpenStudy (anonymous):

c = 9.09 @amistre64

OpenStudy (amistre64):

im not sure what your using to do the calculations with, but you might wanna change its batteries :) the largest degree, 79, will have the largest side value as well .... so NOT 9.09

OpenStudy (anonymous):

23.39?

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

thats better:)

OpenStudy (anonymous):

is that right?

OpenStudy (amistre64):

yes it is

OpenStudy (amistre64):

if you have options, then they prolly rounded the values

OpenStudy (anonymous):

THANK YOU!

OpenStudy (amistre64):

youre welcome, and good luck :)

OpenStudy (anonymous):

Wait but how would you do this?

OpenStudy (amistre64):

its still the law of sine

OpenStudy (amistre64):

you set it up for me so i can see that you are catching on to it

OpenStudy (anonymous):

alright.

OpenStudy (anonymous):

sin 67.38/24 times sin X/26

OpenStudy (amistre64):

looks great now move 26 to the other side 26 sin(67.38)/24 = sin(X) one thing to realize here is that we need to undo a sin function, so inverse each side \[sin^{-1}\frac{26 sin(67.38)}{24} = X\] should do it

OpenStudy (anonymous):

I dont get it?

OpenStudy (anonymous):

I get too small of a answer?

OpenStudy (amistre64):

really? i get about 90 degrees

OpenStudy (amistre64):

hmmm, let me guess, you get 1.5694 right?

OpenStudy (anonymous):

yes.

OpenStudy (amistre64):

:) those are radians, not degrees

OpenStudy (amistre64):

multiply by 180 and divide by pi

OpenStudy (anonymous):

but how does that go with the equation?

OpenStudy (amistre64):

the equation is asking for a value for X in degrees. our solution gets to a point that it gives us the ratio of the sin of X, not the degree of X

OpenStudy (amistre64):

\[sin(X)=\frac{26~sin(67.39)}{24}\] \[sin(X)=\frac{26~sin(67.39)}{24}=1.0000717...\] this is not the degree of X, this is the value of the sine of X; we need to undo the sine function by applying an inverse sine function.

OpenStudy (anonymous):

could you set up the equation for this one?

OpenStudy (anonymous):

@amistre64

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