Help am I right. Please explain to me how to do this?
i take it your trying to work a triangle?
first thing to do is draw a triangle .... and label it up
|dw:1364316468013:dw|
then put in what you know ....|dw:1364316504487:dw|
now you would need to rummage thru your thoughts to see if you have anything that you can use to determine the other values of the triangle
what do we know about the sum of all the angles of a triangle? dont they add up to something specific?
Okay I did 15 sin 62 degrees = b Sin 73 degrees? Now what?
first off, i wouldnt use 73 degrees for that
but other than that, just divide off the sin 79 to determine a value for b
\[\frac{b}{sinB}=\frac{a}{sinA}\] \[\frac{b~sinA}{sinB}=a\]is what i would try out since you seem to be wanting to apply the law of sines
opps one sec.
a = 10.72? @amistre64
.... not quite. \[a=\frac{15sin(62^o)}{sin(39^o)}=abt~21.045^o\]
lol .... thats not spose to be a degree on the end :) 21.045 in length
a = 21.045
thats what my calculator gives me, yes
alright then how would I find c?
|dw:1364317211812:dw|
law of sines works .... so lets keep on using it \[\frac{c}{sinC}=\frac{b}{sinB}\] \[c=\frac{b~sinC}{sinB}\]
c = 9.09 @amistre64
im not sure what your using to do the calculations with, but you might wanna change its batteries :) the largest degree, 79, will have the largest side value as well .... so NOT 9.09
23.39?
@amistre64
thats better:)
is that right?
yes it is
if you have options, then they prolly rounded the values
THANK YOU!
youre welcome, and good luck :)
Wait but how would you do this?
its still the law of sine
you set it up for me so i can see that you are catching on to it
alright.
sin 67.38/24 times sin X/26
looks great now move 26 to the other side 26 sin(67.38)/24 = sin(X) one thing to realize here is that we need to undo a sin function, so inverse each side \[sin^{-1}\frac{26 sin(67.38)}{24} = X\] should do it
I dont get it?
I get too small of a answer?
really? i get about 90 degrees
hmmm, let me guess, you get 1.5694 right?
yes.
:) those are radians, not degrees
multiply by 180 and divide by pi
but how does that go with the equation?
the equation is asking for a value for X in degrees. our solution gets to a point that it gives us the ratio of the sin of X, not the degree of X
\[sin(X)=\frac{26~sin(67.39)}{24}\] \[sin(X)=\frac{26~sin(67.39)}{24}=1.0000717...\] this is not the degree of X, this is the value of the sine of X; we need to undo the sine function by applying an inverse sine function.
could you set up the equation for this one?
@amistre64
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