Question

\[\int\frac{ dx }{ x^2+x^{3/2}-1 }\]

Answer 1

int_{}^{}\frac{ dx }{ x^2+x^{3/2}-1 }\[\int\limits_{}^{}\frac{ dx }{ x^2+x^{3/2}-1 }\]

Answer 2

@experimentX advice him take the perfect square of terms is the right one?

Answer 3

huh ... I think x=t^2 subs

Answer 4

wolf gives weird solution
http://www.wolframalpha.com/input/?i=integrate+1%2F%28x%5E2++%2B+x%5E%283%2F2%29+-+1%29+
let me check on maple.

Answer 5

maple says the same ... weirder than Wolf's

Answer 6

LOL.. try my way. I remember that once my pro solve something like: x^3/2 = 2*1/2 x^2*x^1/2. so the third term of perfect square is 1/2x^1/2. and something more. I am not sure so I dare not to say restlessly, but if both math tools say something weird like that, why don't we try?

Answer 7

are you trying to complete square?

Answer 8

yes

Answer 9

i don't think it can be done ... if the second term were 'x' then it would have been easier.
x^3/2 = 2*1/2 x^2*x^1/2 <--- should be x*x^(1/2)

this would give out x^(1/4) at the end.

Answer 10

yes, my bad. let me try again

Answer 11

wolf decomposes it into partial fraction and integrates it where you get that log ... but i've learnt not to trust machines.

Answer 12

LOL , sir, please, don't confuse me. you told me that you depend on machine too much, now i heard another thing, LOL... which one is correct?

Answer 13

i asked the lawnmower to do the dishes once .... biiiig mistake

Answer 14

@amistre64 what do you mean?

Answer 15

experiment has learnted to not trust machines :)

Answer 16

do you have any idea? I am waiting for help at my post. but stuck here with helper

Answer 17

@Hoa you doing linear algebra bilinear forms?? @amistre64 I depended on wolf too much and sometimes I got busted ;(((

Answer 18

not touch that part yet.

Answer 19

im not seeing a "simple" solution yet.

i know that sometimes, if you work the division you get a polymonial ... sometimes

Answer 20

without target I am lost @cahit do you have answersheet?

Answer 21

no i have not any answer or answer sheet