Use the quadratic formula to find any x-intercepts on the graph of the equation.
y=x^2+6x-10
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OpenStudy (anonymous):
equate with 0
OpenStudy (anonymous):
x^2+6x-10=0
OpenStudy (anonymous):
find values of x, and that's the intersections
OpenStudy (jack1):
-b+or-sqrt ((b^2-4ac)/2a)
OpenStudy (anonymous):
okay, after setting it up to = 0 you have to factor 6 and 10 correct?
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OpenStudy (anonymous):
it's all up to you, whatever method you choose
OpenStudy (anonymous):
yes, you can do it like that
OpenStudy (anonymous):
okay well they have common factors of 2..but I dont know what makes 6 but multiples into 10?
OpenStudy (jack1):
\[y = a x ^{2} + bx + c\]
OpenStudy (anonymous):
yeah, this method can not move you further, use \[x=\frac{ -b+\sqrt{b ^{2}-4ac} }{ 2 }\]
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OpenStudy (anonymous):
Jack1, have shown
OpenStudy (jack1):
dude its over 2a, not 2
OpenStudy (jack1):
and its plus or minus
OpenStudy (anonymous):
yep, it's so buggy
OpenStudy (jack1):
cool website though
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OpenStudy (jack1):
peckce how're u doing?
OpenStudy (anonymous):
Sorry, I am just trying to put all the info in the formula..I really hate this formula.
OpenStudy (anonymous):
@Jack1, yes website is great, but it has leaks
OpenStudy (anonymous):
sometimes i can not enter it, xD
OpenStudy (anonymous):
okay so it should look like this, \[-6\pm \sqrt{6} ^{2}-4(1)(-10) / 2(1)\]
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
leaving us with \[-6\pm \sqrt{36-40}/ 2 = -6\pm \sqrt{-4}/2\]
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
36+40
OpenStudy (anonymous):
so 76
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OpenStudy (anonymous):
\[\sqrt{76}= 39?\]
OpenStudy (anonymous):
no and no
OpenStudy (anonymous):
dang.
OpenStudy (anonymous):
−3±√14
OpenStudy (anonymous):
could you show me how that works?
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OpenStudy (anonymous):
??
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
how works formula u mean?
OpenStudy (anonymous):
no how you got\[-3\pm \sqrt{14} \]
OpenStudy (anonymous):
do you see the formula above?
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OpenStudy (anonymous):
Jack1 told that ax^2+bx+c=0, then mine
OpenStudy (anonymous):
yeah i seen it and last I had was \[-6\pm \sqrt{76}/2 \]
OpenStudy (anonymous):
\[\sqrt{76}=\sqrt{4*14}=2\sqrt{14}\]
OpenStudy (anonymous):
so...
OpenStudy (anonymous):
got it?
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OpenStudy (anonymous):
yes and then we divide 2 into the \[-6 \pm \]?
OpenStudy (anonymous):
yes
OpenStudy (jack1):
dont you mean sqrt 19...?
OpenStudy (anonymous):
therefore it leaves us with \[-3\pm 1\sqrt{14} ??\]
OpenStudy (anonymous):
yep
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OpenStudy (anonymous):
How is the Sqrt of 19?
OpenStudy (jack1):
my intercepts were approx 1.36 and -7.36 ish
exact answers ((sqrt19) - 3) and -((sqrt19) +3)
is that what you got pecke?
OpenStudy (anonymous):
OpenStudy (anonymous):
I was at sqrt of 76/2 since then i've been lost.
OpenStudy (jack1):
as sqrt 76 is 2 x sqrt 19
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OpenStudy (anonymous):
click on my atachment for the answer
OpenStudy (anonymous):
@cmm I did, the graph just should the point at -9... I am unsure of how it's answer when I need it in the radical form.
OpenStudy (anonymous):
therefore would the new answer be \[-3\pm 1 \sqrt{19}\]
OpenStudy (anonymous):
x = 3
OpenStudy (jack1):
[-6 +/- (sqrt 76)] / 2
=-3 +/- (sqrt 76)/2
=-3 +/- (2x(sqrt 19))/2
=-3 +/- (sqrt 19)
2 x intercepts so 2 answers
that's where the plus OR minus comes in, one for each intercept
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
but how come it doesn't have it showing 2/2 = 1 giving it -3+/- 1 sqrt 19?
OpenStudy (jack1):
you can have 1x sqrt 19... but it still just equals sqrt 19...
OpenStudy (anonymous):
sorry i miscalculated((
OpenStudy (anonymous):
Okay, I only ask because my last question like this one, showed the 1
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OpenStudy (anonymous):
Nevermind I was mistaken it didn't
OpenStudy (jack1):
i think it's a waste of space writing the one and it may be mistaken for subscript on the root factor (ie cube root is \[\sqrt[3]{?}\]
OpenStudy (anonymous):
their are two answers (0,0) and (6,0) as the x intercept
OpenStudy (anonymous):
okay so final answer should look like this. \[-3+\sqrt{19}, -3-\sqrt{19}\]
OpenStudy (jack1):
yep, perfect if you want exact answers, 1.36 and -7.36 if you're just looking to plot it by hand
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OpenStudy (anonymous):
nope, thankfully don't have to do that. thank you guys!