What is the value of g[f(4)] for the functions f(x) = 2x + 1 and g(x) = 2x - 5?
what does f(4) equal?
find f(4)
then substite it into g(x)
I don't understand....
when x=4, what does f(x) equal?
f(x) = 2x + 1 when x=4 f(4) = 2(4) + 1 = ??
9?
well, if we follow the usual multiplictaion and addition rules, then yes. f(4) = 2(4)+1 = 9
now, whereever you see an f(4), we can replace it by 9
g(f(4)) = g(9) sooo, g(x) = 2x - 5, g(f(4)) = g(9) = 2(9)-5
I don't understand the answer ._.
you dont understand what 2(9) - 5 is???
g(f(4)) is a notation that i think causes alot confusion. the use of xs in both cases used to throw me for a loop. essentially you have g(x) such that x = f(4), but f(4) = 9 so determine g(9). or, another method is to construct a new function by inserting f(x) int g(x) 2(f(x)) - 5 2(2x+1) - 5 4x+2- 5 4x - 3, is equivalent to g(f(x)); now when x=4 .... you get the same result but in a different construction: 4(4) - 3
its simpler just to work them separately
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