Question

Graph the circle (x+2)2
+ y 2
= 16. @jim_thompson5910

Answer 1

(x+2)^2 + y^2 = 16

is the same as

(x-(-2))^2 + (y-0)^2 = 4^2

so are you able to determine the center and radius?

Answer 2

2?

Answer 3

2 is what

Answer 4

the radius

Answer 5

no, but close

Answer 6

4

Answer 7

compare

(x-(-2))^2 + (y-0)^2 = 4^2

to

(x-h)^2 + (y-k)^2 = r^2

Answer 8

you'll see that r^2 = 16 ----> r = 4

Answer 9

so radius is 4

Answer 10

yep, good you got it the second time

Answer 11

and where should my center be?

Answer 12

the center is what

Answer 13

well (h,k) is your center, so ???

Answer 14

if you can find h and k, then you can find the center

Answer 15

2,2?

Answer 16

no

Answer 17

again compare

(x-(-2))^2 + (y-0)^2 = 4^2

to

(x-h)^2 + (y-k)^2 = r^2

Answer 18

h = ???

k = ???

Answer 19

hmm im not sure what to do there

Answer 20

notice how the -(-2) part matches up with the -h part

Answer 21

so h = -2

Answer 22

y-0 matches up with y-k

so k = 0

Answer 23

(h,k) = (-2,0)

Answer 24

your center is (-2,0)

Answer 25

ohh

Answer 26

That's enough info to graph

Answer 27

ok thanks :)

Answer 28

yw