Evaluating limit. There is a general rule about exponents that is very important that I forgot exactly how it goes. I know if exponent in denominator and numerator are the same I need to divide coefficients but i'm not sure about the other two...

See problem attached

I get 2x+ 6 / 3x^2 +12

exponent on numerator is greater so does that mean that answer is zero ?

Question

Evaluating limit. There is a general rule about exponents that is very important that I forgot exactly how it goes. I know if exponent in denominator and numerator are the same I need to divide coefficients but i'm not sure about the other two... 

See problem attached

I get 2x+ 6 / 3x^2 +12 

exponent on numerator is greater so does that mean that answer is zero ?

anonymous · Answer

attachment

raden · Answer

agree

abb0t · Answer

Basically, you're taking the derivative of the numerator function and denominator function to evaluate.

abb0t · Answer

But you don't need to use L'hopitals for the limit. You can easily see that that you get zero as the limit.

anonymous · Answer

because exponent on top is greater than bottom?

anonymous · Answer

I mean lower than bottom?

abb0t · Answer

Yes. If you kept taking the derivative of the numerator, it would eventually reach zero. And zero divided by anything is zero.

anonymous · Answer

what if the exponent is greater on top than bottom?

abb0t · Answer

What do you think is your answer? You could have to look at the limits from both sides from infinity.

anonymous · Answer

if exponent on  top is greater than bottom answer would be infinite?

abb0t · Answer

It would not exist. Because the limit as you approach the function from the left (negative) is not the same as when you approach from the right (positive)

anonymous · Answer

oh yeah! got it! thank you!