Question

BEEN STUCK ON THIS ONE FOREVER HELP PLEASE?? the mean value theorem applies to f(x)=1/x on the interval [1,3],find all values of c in the interval such that f'(c)=f(3)-f(1)/3-1

Answer 1

i finally got it !!

Answer 2

take the derivative of f(x), which should be f'(x) = -1/x^2. Set that expression equal to whatever f(3)-f(1)/3-1 is. Then solve.

Answer 3

f'(x) = -1/x^2
By MVT, f'(c) = -1/c^2 = (1/3 - 1/1)/(3-1) = (1-3)/6 = -1/3
So, c = +/-sqrt(3)

Answer 4

congratulation

Answer 5

yay

Answer 6

yes !! lol been on it for 2hrs