Question

(K^1/3)^-5 OVER (k^8)^1/6=

need help with this one.

Answer 1

1/3 times -5 = ???

Answer 2

-5/3

Answer 3

8 times 1/6 = ??

Answer 4

4/3

Answer 5

now you subtract the expoennts

-5/3 - 4/3 = ???

Answer 6

gives me -9/3

Answer 7

well I get a final of 1/k^3

Answer 8

good, -9/3 = -3

Answer 9

k^(-3) = 1/( k^3 )

Answer 10

Thanks Jim. I really appreciate the help :)

Answer 11

np