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Verifying trig identities: sec(x+y)=sec x sec y/1-tan x tan y
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You can write it as: \[\sec(x+y) = \frac{1}{\cos(x+y)}\] And after that use: \[\cos(x+y) = \cos(x)\cdot \cos(y) - \sin(x) \cdot \sin(y)\]
Can you just try once??
Then can I divide by sin x sin y to get it on the bottom?
You should divide by cos(x)cos(y) as seeing from what our RHS wants,...
Please show me what are you doing? Otherwise we will not be in sync..
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It's ok I figured it out(: thanks
If in problem then feel free to tell me..
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