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find the sum to the required number of terms for the geometric series 1-5+25-125...to 6 terms
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do you know formulas?
here b1=1 and q=-5
you need to find sum of them all till n=6
s=b1*(1-q^n)/(1-q)
substitute numbers and you will get the answer
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i got 15625/6
is it ok to get like a decimal
no
i got 2604
check again, you missed here (1-q^n)
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don't forget 1
after plugging in, it would be 1(1-(-5)^6) / 1-(-5) 1(1-15625)/ 6 -2604
is that right?
yes
ok thank you !
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