Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

find the sum to the required number of terms for the geometric series 1-5+25-125...to 6 terms

OpenStudy (anonymous):

do you know formulas?

OpenStudy (anonymous):

here b1=1 and q=-5

OpenStudy (anonymous):

you need to find sum of them all till n=6

OpenStudy (anonymous):

s=b1*(1-q^n)/(1-q)

OpenStudy (anonymous):

substitute numbers and you will get the answer

OpenStudy (anonymous):

i got 15625/6

OpenStudy (anonymous):

is it ok to get like a decimal

OpenStudy (anonymous):

no

OpenStudy (anonymous):

i got 2604

OpenStudy (anonymous):

check again, you missed here (1-q^n)

OpenStudy (anonymous):

don't forget 1

OpenStudy (anonymous):

after plugging in, it would be 1(1-(-5)^6) / 1-(-5) 1(1-15625)/ 6 -2604

OpenStudy (anonymous):

is that right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok thank you !

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!