Solve the following system of equations:x + 2y + z = -2-2x + 4y - 4z = -222x + y + 2z = 5
@jim_thompson5910 @Mertsj
Could you please make a clearer post?
is the actual problem this? x + 2y + z = -2 -2x + 4y - 4z = -22 2x + y + 2z = 5
Solve the following system of equations:
\[x + 2y + z = -2-2x + 4y - 4z = -222x + y + 2z = 5 \]
That's how my worksheet has it written but it could be the way you have it @jim_thompson5910
that's how the worksheet wrote it out? literally that format?
yes
well that's just lousy
it's hard to tell where one equation ends and where one equation begins what I wrote out is just one possibility of what they meant
I think so... it says under that the possible answers are:
(3, -3, 1) (-3, -3, 1) (3, -3, -1) (-3, 3, 1)
ok let me try out a few things real quick
ok it has to the be that because the other possibilities give different answers
Start off by solving the first equation for x x + 2y + z = -2 x + z = -2 - 2y x = -2 - 2y - z ------------------------------------------------------- Now plug x = -2 - 2y - z into the second equation -2x + 4y - 4z = -22 -2(-2 - 2y - z) + 4y - 4z = -22 4 + 4y + 2z + 4y - 4z = -22 4+8y-2z = -22 8y-2z = -22 - 4 8y-2z = -26 ------------------------------------------------------- Then plug x = -2 - 2y - z into the third equation 2x + y + 2z = 5 2( -2 - 2y - z) + y + 2z = 5 -4 - 4y - 2z + y + 2z = 5 -4-3y = 5
From here, you need to solve -4-3y = 5 for y Once you have the value of y, you solve 8y-2z = -26 for z (after plugging in the value of y found previously)
Finally, once you know y and z, you can use them to get x by plugging them into x = -2 - 2y - z
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