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OpenStudy (anonymous):
What is the simplified form of
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OpenStudy (anonymous):
OpenStudy (studiousstudent):
x-2
OpenStudy (studiousstudent):
2x/x = 1x or x
OpenStudy (studiousstudent):
-6 / -3 = __
OpenStudy (anonymous):
my answer: x - 2, with the restriction x ≠ 2
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jimthompson5910 (jim_thompson5910):
2x - 6 factors to 2(x-3)
OpenStudy (anonymous):
answer choices: 2, with the restriction x ≠ 3
x - 2, with the restriction x ≠ 2
3, with the restriction x ≠ 2
x - 3, with the restriction x ≠ 3
jimthompson5910 (jim_thompson5910):
\[\Large \frac{2x-6}{x-3}\]
\[\Large \frac{2(x-3)}{x-3}\]
jimthompson5910 (jim_thompson5910):
I'm sure you see what cancels
The restriction must be x ≠ 3 because that makes the denominator equal to zero
OpenStudy (anonymous):
So it's D
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jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
the x-3 terms cancel out and go away
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
without the restriction of 2, right?
jimthompson5910 (jim_thompson5910):
\[\Large \frac{2(x-3)}{x-3}\]
would turn into
\[\Large \frac{2}{1}\]
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jimthompson5910 (jim_thompson5910):
which is just 2
OpenStudy (anonymous):
okay... so 2 with the restriction of 3
jimthompson5910 (jim_thompson5910):
So \[\Large \frac{2x-6}{x-3} = 2, \ \text{where} \ x \neq 3\]
jimthompson5910 (jim_thompson5910):
yep
OpenStudy (anonymous):
thank you:)
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