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Mathematics 31 Online
OpenStudy (anonymous):

What is the simplified form of

OpenStudy (anonymous):

OpenStudy (studiousstudent):

x-2

OpenStudy (studiousstudent):

2x/x = 1x or x

OpenStudy (studiousstudent):

-6 / -3 = __

OpenStudy (anonymous):

my answer: x - 2, with the restriction x ≠ 2

jimthompson5910 (jim_thompson5910):

2x - 6 factors to 2(x-3)

OpenStudy (anonymous):

answer choices: 2, with the restriction x ≠ 3 x - 2, with the restriction x ≠ 2 3, with the restriction x ≠ 2 x - 3, with the restriction x ≠ 3

jimthompson5910 (jim_thompson5910):

\[\Large \frac{2x-6}{x-3}\] \[\Large \frac{2(x-3)}{x-3}\]

jimthompson5910 (jim_thompson5910):

I'm sure you see what cancels The restriction must be x ≠ 3 because that makes the denominator equal to zero

OpenStudy (anonymous):

So it's D

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

the x-3 terms cancel out and go away

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

without the restriction of 2, right?

jimthompson5910 (jim_thompson5910):

\[\Large \frac{2(x-3)}{x-3}\] would turn into \[\Large \frac{2}{1}\]

jimthompson5910 (jim_thompson5910):

which is just 2

OpenStudy (anonymous):

okay... so 2 with the restriction of 3

jimthompson5910 (jim_thompson5910):

So \[\Large \frac{2x-6}{x-3} = 2, \ \text{where} \ x \neq 3\]

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

thank you:)

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