Question

Find the vector equation and parametric equations for L2, the straight
line passing through the point A(4; 1; 2), and parallel to the line
described by the symmetric equation x-3=(y-6)/3=(z-1)/3

Answer 1

Not meant to be semicolons between the numbers on point A sorry. I know i need to use the equation \[R=r+tv\] but i'm not sure how to get the symmetric equation into a point where i can use it.

Answer 2

x-3=(y-6)/3=(z-1)/3=t
so:
x-3=t
y-6=3t
z-1=3t
or:
if r=(3,6,1) and v=(1,3,3), then:
R=(3,6,1)+t(1,3,3)

Answer 3

Thanks for the answer. Sorry to ask but then how does point A come into the question?

Answer 4

what I gave you is the vector expretion og the line x-3=(y-6)/3=(z-1)/3. It is not the final answer. You have to take the direction vector from this line and aply it to the point A to get the final answer

Answer 5

Okay that makes sense. thanks.

Answer 6

yw