Question

What are the x-intercept(s) of the graph of y + 6 = x^2 − x?

A.) (−2, 0) and (3, 0)
B.) (−2, 0) and (−3, 0)
C.) (2, 0) and (−3, 0)
D.) (2, 0) and (3, 0)

Answer 1

rearrange the equation to the form y = ax^2 + bx +c first

Answer 2

x intercepts would occur at y=o
so replace y with 0
therefore 0= ax^2 + bx +c

Answer 3

Firstly you can subtract 6 from both sides of the equation leaving you with:
y = x^2-x-6
(x ...)(x ...) = 0
This is a trick i learned once. The values on the ... must be so such that. the product of bots equals c (-6) and the sum of both equals b (-1)

When we try a few values we find:
(x-3)(x+2)=0
This equation only fits if one of these ( (x-3) or (x+2) ) equals zero. This is only the case if x = 3 or x = -2.

And of course it only intercepts the x plane is y = zero. So the right answer here is
(x,y) = (-2,0) and (3,0)

Answer 4

oh my goodness thank you both!! ur the best!!!!