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Find the arc length of a sector that is 125° and has a radius of 20 in.
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I think i know how to do it but im not sure is it 3.14 x 20 x 20 = 1256 Arc length = 125/360 x 1256 = 436.11
|dw:1364909347262:dw| Arc length is proportioanl to the angle in radians. \[L={\theta\over360}\times2\pi r\]
So im right? with 436.11?
you calculated the Area of the sector. by usgin \(\pi r^2\).
im confused
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Area of sector: \[A={\theta\over360}\times \pi r^2\] Length of arc: \[L={\theta\over360}\times2\pi r\]
kapeesh?
\[arclength=\theta \times r\] where r is the radius and theta is angle in radians
okay yes i got it! thanks :)
yer welcome.
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