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Solve. 1 over 25 = 5^(x + 4)?
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\[\frac{ 1 }{ 25 }=5^{x+4}\]
same process as the last question the base on both sides of the equation is 5 rewriting \[5^2 = 5^{x + 4}\] equate the powers and solve for x
-2, but yes
so is it 1/25 or 25...?
if you couldnt determine a like base, logging it would suffice
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oops it should be misread the question. \[5^{-2} = 5^{x + 4}\]
ln(1/25) = ln(5^(x+4)) ln(1} - ln(25) = ln(5) (x+4) - ln(25)/ln(5) = x+4 - ln(25)/ln(5) - 4 = x
why not just equate the powers since the bases are the same. -2 = x + 4
you can, but spose you didnt notice a similarity of bases ...
so x=-6, right?
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looks like it...
Okay, thanks!
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