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how do you find dy/dx of r=1+cos(theta) as a function of theta?
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derivative of cos = - sin
That's just the derivative of 1+cos(theta) right? So it would be -sin(theta)
are u sure it wants dy/dx or dr/dtheta?
I didnt think it was possible to find dy/dx, but thats what the worksheet says
Yeah, of course it is (possible) :)
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It's probably just a typo, aka using variables interchangeably. That happens a lot.
i think it means derivative as a function of theta so ya u can just say its -sin (theta)
yep
But where's the adventure in that :D \[\huge x=r\cos(\theta)\]\[\huge y=r\sin(\theta)\]
wherse the fun in that |dw:1364950377114:dw|
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