Question

find the equation of parabola with vertex (2,-3) directrix x=-2

Answer 1

@jim_thompson5910

Answer 2

what's the distance from (2,-3) to the line x = -2

Answer 3

k i have the answer can u check if it is correct or not

Answer 4

sure

Answer 5

\[(y-3)^{2} =8(x-2)\]

Answer 6

no it is +3

Answer 7

that's not correct

Answer 8

the directrix of (y+3)^2 =8(x-2) is x = 0, not x = -2

Answer 9

but i got 8

Answer 10

what is incorrect?

Answer 11

@jim_thompson5910

Answer 12

it should be (y+3)^2 =16(x-2)

Answer 13

the focal distance is p = 4

you would then multiply that by 4 to get 16

Answer 14

opps i did 4*2 okay sorry

Answer 15

np

Answer 16

so the answer is (y+3)^2 = 16(x-2)

Answer 17

yes

Answer 18

k i have 1 more

Answer 19

ok

Answer 20

find the equation of hyperbola with vertices (2,-3) and (2,5) and foci (2,-4) and( 2,6)

Answer 21

you got what

Answer 22

\[\frac{ (x-2) ^{2}}{ 9 }- \frac{ (y-1)^{2} }{ 16 }\]

Answer 23

that's not correct

Answer 24

:(

Answer 25

you're on the right track though

Answer 26

you just have a few things mixed up

Answer 27

like what?

Answer 28

well the signs are mixed up for starters

Answer 29

it should be in the form


- ((x - h)^2)/(a^2) + ((y - k)^2)/(b^2) =1

Answer 30

and what is the correct answer?

Answer 31

you tell me, try it again and tell me what you get

Answer 32

okay

Answer 33

\[\frac{ (y-1) ^{2}}{ 16}-\frac{ (x-2) }{ 9 }=1\]

Answer 34

much better

Answer 35

so this is correct?

Answer 36

oh you're missing a square over the (x-2), but yes it is

Answer 37

oh sorry k thank you like i told u yeasterday day u are a great teacher

Answer 38

thx and it's ok

Answer 39

thank you!

Answer 40

yw