What do you with the degrees when dividing?
\[\frac{ 41.32^o }{ -36.87^o }\]
it's just the same as dividing normal numbers. still the unit remains degrees.
@pangyaPrince what if it is like this \[\frac{ 58.07 V (volts)<41.32^o }{ 5 ohms <-36.87^o }\]
hm.. i'm not familiar with these. but since you're diving volts to ohms, are you solving for a current? correct me if i'm wrong.
If you wrote it like this: \[\frac{41.32\text{degrees}}{-36.87 \text{degrees}}\] then units would cancel:\[\frac{41.32}{-36.87}\]
sorry for the wrong information. I thought it won't cancel because it's a unit.
Units cancel if they are the same in numerator and denominator, however, what she posted is a special case since you also have to deal with less than equal signs
thanks guys for the help, i think i got it now
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