Question

( cos theta - cot theta ) / 1- sin theta = - cot theta
prove the identity.. i'm having troubling making the LS equal the RS

Answer 1

hmm, i'll try not to draw this time :D

Answer 2

lol

Answer 3

(cosθ-cotθ)/1-sin θ = - cot θ

Work with left side
(cosθ- cosθ/sinθ) / 1-sinθ
(cos/1 - cosθ/sinθ) / 1-sinθ
(cosθsinθ-cosθ)/sinθ / 1-sinθ
cosθ (sinθ-1)/ sinθ / 1-sinθ
Now at this part, cosθ become cotθ because cosθ/sinθ = cotθ
cotθ( sinθ-1) / 1-sinθ
(sinθ-1) and 1-sinθ cancel out left with a -cotθ = -cotθ

Hope it's not too confusing :|

Answer 4

Looks worse than the drawings

Answer 5

i take that as a compliment :X

Answer 6

cos(a)-cot(a)/1-sin(a)
=[sin(a)cos(a)-cos(a)]/sin(a)(1-sin(a))
=cos(a)(sin(a)-1)/-[sin(a)(sin(a)-1]
=-cot(a)

Answer 7

\(\LaTeX\) is very easy to learn

Answer 8

where

Answer 9

type `\(\LaTeX\)` to produce this: \(\LaTeX\)

Answer 10

type `\(\frac{2x}{5}\)` to produce this: \(\frac{2x}{5}\)

Answer 11

\(\LaTeX\)

Answer 12

Congratulations. That's the equivalent of learning how to print "Hello World" in java

Answer 13

cool! thx :D

Answer 14

@soapia it helps if you write out what i did on paper, so u can see it
or maybe @Hero can \(\LaTeX\) for u

Answer 15

@Shido88, you can \(\LaTeX\)

All you do is just put everything you type between `\( \)` Think of them as quotation marks for math

Answer 16

(cosθsinθ-cosθ)/sinθ / 1-sinθ
cosθ (sinθ-1)/ sinθ / 1-sinθ ... you cross multiplied the numerator..?

Answer 17

There are some special symbols though. For example, to do fractions, you have to use \frac{a}{b}, where a = numerator expression, b = denominator expression

Answer 18

whoops.. i mean this step (cos/1 - cosθ/sinθ) / 1-sinθ to this step..
(cosθsinθ-cosθ)/sinθ / 1-sinθ u cross multiplied the numerator?

Answer 19

So typing `\(\frac{a}{b}\)` produces: \(\frac{a}{b}\)

Answer 20

@soapia no, I factor out the cosθ

Answer 21

\(Shido\) oh ok

Answer 22

`\(2x^2\)` produces \(2x^2\)

Answer 23

`\(2 \times 5\)` produces \(2 \times 5\)

Answer 24

`\(16 \div 4 = 4\)` produces \(16 \div 4 = 4\)

Answer 25

`\(\cos\theta\)` produces \(\cos\theta\)

Answer 26

`\(x = \frac{b \pm \sqrt{b^2 - 4ac}}{2a}\)` produces \(x = \frac{b \pm \sqrt{b^2 - 4ac}}{2a}\)

Answer 27

You only use the \ symbol before tag words like \frac \cos \times \div \sqrt, etc...

Answer 28

And each line of algebraic expressions go between `\( \)`

Answer 29

ahh computer froze for a while after doing Latex!
@soapia sorry for late reply, you don't exactly multiply them cuz this is a minus in between. When it's a multiplication or division in between then you can but this is minus, so just basictly combine the top part and bottom part. Bottom part is the same so understood to be itself

Answer 30

@Hero where did u learn all this?

Answer 31

A lot of users know how to use \(\LaTeX\). there's a whole group dedicated to it. There are books written on it. It's been out since the 60's or 70's I believe.

Answer 32

No, that doesn't imply that I've been around for that long.

Answer 33

http://en.wikipedia.org/wiki/LaTeX

Answer 34

lol, i know lots of people knows how to use it but it just seems amazing that you can remember to do all that. Maybe I'm just new to it i guess :)

Answer 35

haaa! found a youtube video lol !

Answer 36

Be careful, there are different quotation marks that are used. Here, we use `\( \)`
or `\[ \]`

Answer 37

Others use `& &` or `$ $` or `; ;`

Answer 38

Cool! will try next time

Answer 39

The first one means "begin Latex" the second one means "end Latex"

Answer 40

I see