Do they have TikZ and PGF support on OpenStudy?
Does not seem like it, but I thought I might be missing something if they did have it hidden in here. Might be a nice way to do more accurate drawings and the linear algebra support is great. \[ \begin{tikzpicture}[ pile/.style={thick, ->, >=angle 45} ] \coordinate (A) at (0,0); \coordinate (B) at (0,2); \coordinate (C) at (3,1); \coordinate (D) at (3,3); \draw[pile] (A) -- (B) node[midway,left]{$\vec{u}$}; \draw[pile] (A) -- (C) node[midway,below]{$\vec{v}$}; \draw[pile] (B) -- (D) node[midway,above]{$\vec{v}$}; \draw[pile] (C) -- (D) node[midway,right]{$\vec{u}$}; \draw[pile,dashed] (A) -- (D) node[sloped,midway,above]{$\vec{u}\oplus\vec{v}$} node[sloped,midway,below]{$\vec{v}\oplus\vec{u}$}; \end{tikzpicture} \]
At the {Math} \(\large \cap\) {Philosophy}... \[\Large{\sum}_{k_0=g^it_0}^{e^rG_0}D^ek_ar^{t^{es}} \doteq M^i_nd\] ...the Cartesian \(k_0g^it_0~e^rG_0\) sum. See attached for my orginal PDF version.
lol
So, you get that, eh? Math people see it. Philosophy do not.
A reference image for those new to matrix multiplication.
wonderful now my brain hurts congrats -.-
Hehe. Well, it is a Math/Philosophy joke! What do you expect!
im dying slowly in the inside lol jk :P
The Cogito is Descartes' most quoted piece: Cogito ergo sum = I think, therefore I am. But Descartes is also one of the world's most famous mathematicians. Cartesian coordinates and the entire geometric plane system! So he sits at the intersection of math and philosophy. Now, you take someone with a love of puns who has taken both math and philosophy, and guess what the result is...
you! lol jk
`Text box?` Ahh... that is it. $$`test`$$ `$$test$$` Hmmm.... can't mix them.
``` from numbers import Number class One: def __add__(self, other): return self if other == 0 else 0 __sub__ = __add__ def __mul__(self, other): if isinstance(other, Number): return 0 if other == 0 else self return other def __div__(self, other): if other == 0: raise ZeroDivisionError return self __truediv__ = __div__ def __rdiv__(self,other): return other __rtruediv__ = __rdiv__ __radd__ = __add__ __rsub__ = __add__ __rmul__ = __mul__ def __str__(self): return 'one' __repr__ = __str__ def __neg__(self): return self def __bool__(self): return True one = One() zero = 0 ```
@DebbieG /sigh I made this for babygirl1223, but not gonna share it until she gets this right! \(3xy\left(\dfrac{\color{red}{\cancel{\color{black}{x}}}y^{\color{red}{\cancel{\color{black}{2}}}}}{\color{red}{\cancel{\color{black}{xy}}}}+\dfrac{2x^{\color{red}{\cancel{\color{black}{2}}}}\color{red}{\cancel{\color{black}{y}}}}{\color{red}{\cancel{\color{black}{xy}}}}\right)\)
Hah... very nice! :)
404 Joke Not Found
@Compassionate stalking me through my asked questions? Hehe.
I prefer the term "Yandere."
Just think, by posting you will being Jamie back. She will read that again, and her brain will hurt again.
Isn't it our job as her elders to make her head hurt? A little 'sumthing' never hurt anyone, right? (;
Ha, but you don't even know the joke! You said it was not found.
I've solved the sum. I have yet to see the joke. My head doesn't hurt - my head has no idea what I'm looking at. Math and philosophy or intersections? I'm sorry - but I read too much Pascal to understand simple math jokes.
You'll have to spoon feed me with dry rice for this one.
OK, if you solved the sum, what is it?
Guuuuys my poor head.. #unCompassionate
Muhahaha
I forgot this glorious thread existed.
Yes, hiding out here, it lives in the darkness. Squirrels kept linking this pic: https://scontent-b-dfw.xx.fbcdn.net/hphotos-xfp1/t1.0-9/10307183_10201196497473614_4103644827666756531_n.jpg So I made that one to tease him back.
Eric, you need to get your brain checked.
Update: I don't remember what the joke was or the visual summation. Cannot compute
Learn philosophy!
@jigglypuff314 There is also this way to get the inverse: \(\left[ \begin{array}{cc|cc} a & b & 1 & 0\\ c & d & 0 & 1 \end{array} \right] \) Start with that, then solve what is left of the | to \([\begin{smallmatrix}1&0\\0&1 \end{smallmatrix}]\) and then the right is the inverse.
If they do not know the determinant*adjoint method, that is another way to go. All comes down to what they know.
*blinks* *scratches head* I'll figure that out at some point :P I just googled how to get the matrix inverse on the spot specifically to help on that question, but Matrices are one topic I know that I don't know >,<
I had an intro linear algebra course.
If you know gauss-jordan eliminaion, which is a way to solve systems of equations in matrices, you can also use it to find the inverse of a matrix.
*completely gone over my head* I suppose I should study up on my Matrices ^_^"
I have some worked examples you can go over and ask about: http://openstudytutorials.weebly.com/by-helper.html#e.mccormick
oh! great, thanks! :)
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