Question

Calculate the change in internal energy (delta E) for a system that is absorbing 35.8 kJ of heat and is expanding from 8.00 to 24.0 L in volume at 1.00 atm. Answer in kJ

q = 35.9 kJ
delta V = 24 L - 8.00 L =16 L
p = 1.00 atm

w=-p delta V

w = (-1.00atm)(16L)
= 16 atm * L

atm --> J
(16 atm * L) * 103 J / 1 L* atm

J -> kJ

1620 J * 1 j / 1000 kJ = 1.6 kJ

Answer not listed. What am I doing wrong?

Answer 1

oh wait I think there's one more step!
delta E = q + w

Answer 2

delta E = 35.8 kJ - 1.6 kJ = 34.2