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Mathematics 23 Online
OpenStudy (anonymous):

HELP ON SIMPLE ALGEBRA!!

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

@robtobey

OpenStudy (anonymous):

I think the first one is B

OpenStudy (anonymous):

@.Sam.

OpenStudy (anonymous):

no, it is not B

OpenStudy (anonymous):

\[y-y_1=m(x-x_1)\] is the "point - slope" form in your case \(x_1=7,y_1=-2, m=-3\)

OpenStudy (anonymous):

Then it'd have to be D right?

OpenStudy (anonymous):

make a direct substitution in to the formula and get \[y-(-2)=-3(x-7)\] which you would then rewrite as \[y+2=-3(x-7)\]

sam (.sam.):

Ah too fast @satellite73 !

OpenStudy (anonymous):

you can splain the next one

OpenStudy (anonymous):

Ah I see now, so for the 2nd one I think it's A but I could be completely wrong again... @.Sam. @satellite73

OpenStudy (anonymous):

i lied it's d

sam (.sam.):

If its parallel, then the gradient is the same, so, we've got (4,-6) and m=-1/2, then use the point slope form \[y-y_1=m(x-x_1)\] \[y-(-6)=-\frac{1}{2}(x-4)\] \[y=-\frac{1}{2}x-4\]

sam (.sam.):

@haleycoulter Yes you've got it

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