Question

-√3(√-3)
help me pleasee

Answer 1

\(\sqrt{-3}=\sqrt{3}i\)

Answer 2

i know this is with i agai

Answer 3

so
\[-\sqrt{3}\times \sqrt{3}i=-3i\]

Answer 4

ohh so anything with a negative is and imaginary number right

Answer 5

if you have a negative number inside the radical, then it comes outside as \(i\)

Answer 6

yeah because a negative isnt possible in square root

Answer 7

for example \(\sqrt{-25}=\sqrt{25}i=5i\) and
\[\sqrt{-3}=\sqrt{3}i\]

Answer 8

i have a few more question like this can i show you and can you tell me if im doing it right?

Answer 9

√-25√-9
its going to be 5i 3i right?

Answer 10

yes, that would be the first step

Answer 11

the second step would be to actually multiply and get
\[5i\times 3i=15i^2=15\times (-1)=-15\]

Answer 12

the i goes away?

Answer 13

yes, because \(i=\sqrt{-1}\) and so \(i^2=-1\)

Answer 14

oh that makes sense
and im sorry i just have two more if u could please check them as well
(6i)2 which would be 36i right but if i multiplied 36 by -1 then i get -36
then theres (2+3)(2-3i) im not sure about this one like is it going to be like 5*2-3(-1) ?

Answer 15

thanks for helping me out im stuck with all this and guys are the best :D