Ask your own question, for FREE!
Chemistry 18 Online
OpenStudy (anonymous):

#1: The concentration of a solution can be described in several ways. In which of these ways do you calculate the moles of a solute divided by the kilograms of solvent? A. molality B. molarity C. mole fraction D. mass percent **my answer: A. molality is that right? @chmvijay :)

OpenStudy (chmvijay):

A. molality

OpenStudy (anonymous):

#2: Which of the following is the number of moles of a solute that is dissolved in 1 liter of solution? A. molarity B. molality C. mass percent D. mole fraction **my answer: A. molarity is that right? and yayy for #1!!

OpenStudy (chmvijay):

A. molarity

OpenStudy (anonymous):

#3: You want to determine the concentration of a liquid solute dissolved in a liquid solvent. Which of the following would be the best to use? A. molarity B. molality C. mass/mass percent D. volume/volume percent **my answer; D. volume/volume percent is that correct?

OpenStudy (chmvijay):

D. volume/volume percent

OpenStudy (anonymous):

#4: Which colligative property is employed when salt is put on an icy sidewalk to melt ice? A. boiling-point elevation B. freezing-point depression C. vapor-pressure lowering **my answer: A. boiling-point elevation is that right?

OpenStudy (chmvijay):

freezing-point depression

OpenStudy (anonymous):

#5: You have two liquids in solution. The solutions have different boiling points. Which of the following is the best method to separate them? A. distillation B. fractionation C. filtration D. osmosis **my answer: A. distillation is that right?

OpenStudy (chmvijay):

A. distillation

OpenStudy (anonymous):

okay, so #4 is for sure, definitely B? freezing-point depression is the answer to #4? not boiling point?

OpenStudy (chmvijay):

yaaa LOL:)

OpenStudy (chmvijay):

why D option is not there in question 4 :)

OpenStudy (anonymous):

oh there's only 3 options for that one :) okay, so B it is!! :D

OpenStudy (chmvijay):

:)

OpenStudy (anonymous):

thanks!!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!