Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

3 EASY ALGEBRA PROBLEMS

OpenStudy (anonymous):

OpenStudy (aravindg):

1. slope intercept form is y=mx+c

OpenStudy (aravindg):

where m is slope and c is y intercept

OpenStudy (aravindg):

Check the options if you have an equation in that form

OpenStudy (anonymous):

which question is this for? @AravindG

OpenStudy (aravindg):

1st one

OpenStudy (comm.dan):

Do you remember the formula for finding the slope of two points? @haleycoulter

OpenStudy (anonymous):

c @AravindG

OpenStudy (aravindg):

yep you are right !

OpenStudy (comm.dan):

Do you remember the formula for slope intercept form? @haleycoulter

OpenStudy (aravindg):

for next question ..first find equation of given line .

OpenStudy (aravindg):

do you know how to get the equation ?

OpenStudy (comm.dan):

What do you think the answer is for the second equation and third equation? @haleycoulter

OpenStudy (anonymous):

I think that one is B @AravindG

OpenStudy (comm.dan):

You think that the 2nd problem is B? @haleycoulter

OpenStudy (anonymous):

yeah

OpenStudy (aravindg):

wait i need to check that

OpenStudy (aravindg):

what dd you get as equation of the given line ?

OpenStudy (anonymous):

I have no idea...

OpenStudy (aravindg):

ok you see the given line has intercepts both on x axis and y axis .So you can use intercept form to get eqn of line x/a+y/b=1 where a is x intercept , b is y intercept

OpenStudy (aravindg):

now can you telll ?

OpenStudy (anonymous):

it's not clicking sorry :/

OpenStudy (anonymous):

IMPORTANT LINE RELATED EQUATIONS TO KNOW AND MEMORIZE slope formula m= slope/ gradiant -- same thing \[m=\frac{y_2-y_1}{x_2-x_1}\] standard formula \[Ax+By=C\] point-slope formula \[y-y_1=m(x-x_1)\] slope-intercept formula b= y-intercept -- in the form of (0,y) \[y=mx+b\]

OpenStudy (comm.dan):

A is the x intercept and B is the y intercept. @haleycoulter

OpenStudy (aravindg):

seems you need to first thoroughly go through basic equations first ...check my tutorial : http://openstudy.com/updates/50f8cc3fe4b027eb5d9a556a

OpenStudy (comm.dan):

@haleycoulter She says that she thinks that the answer is C. @AravindG

OpenStudy (anonymous):

well skipping to the third question I got the answer A

OpenStudy (aravindg):

when did she say that ?

OpenStudy (aravindg):

why skip ?

OpenStudy (comm.dan):

She sent it to me in an email addressed to me.

OpenStudy (aravindg):

Can you tell me why you think it is C @haleycoulter ?

OpenStudy (comm.dan):

@haleycoulter We will help you only if you don't skip the questions that you posted.

OpenStudy (aravindg):

^^ yep we are here to learn not give you answers directly :)

OpenStudy (aravindg):

guessing is a bad option

OpenStudy (anonymous):

Well for the third question I did y2-y1/x2-x1 that's how I got 1

OpenStudy (comm.dan):

Yes, I agree with @AravindG

OpenStudy (aravindg):

how ? 4-3= ? 1-2= ?

OpenStudy (anonymous):

and the 2nd question i actually think it's A because slope: (y-y)/(x-x) (5-3)/(3-0) = 2/3 Slope of a line perpendicular to that is the negative reciprocal: -3/2 y = mx + b -3 = (-3/2)(2) + b b = 0 y = -3/2x

OpenStudy (anonymous):

oh shoot @AravindG my bad i screwed that up it should be -1

OpenStudy (aravindg):

\[\checkmark \]

OpenStudy (comm.dan):

Yes, good job, now do the second problem. @haleycoulter

OpenStudy (aravindg):

wait a sec ..how did you find the slope like that ?

OpenStudy (aravindg):

for findind slope it is slope=difference of y coordnates/diff of x coordinates

OpenStudy (aravindg):

that will give me 3-0/0-(-5)

OpenStudy (anonymous):

ugh I give up I'm just guessing on that one :/

OpenStudy (comm.dan):

I learned it this way \[y^{2}-y^{1} \over x^{2}-x^{1}\]

OpenStudy (aravindg):

why give up ? you are almost there !

OpenStudy (comm.dan):

No guessing, that is not the way to do math. @haleycoulter

OpenStudy (anonymous):

Oh well

OpenStudy (aravindg):

so do you understand what I said above ?

OpenStudy (anonymous):

no idea

OpenStudy (aravindg):

find slope as I showed above

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!