Question

Verify:
1.(cscx/cosx)-tan=cotx

Solve:
2. cos^2x+sin(2x)-sinx-1=-sin^2x

Answer 1

simplify csc x/cot x first

Answer 2

1)
left side:
\[\frac{ \frac{ 1 }{sinx } }{ cosx }-\frac{ sinx }{ cosx}\]
\[\frac{ ccosx-\sin^2cosx }{ \cos^2xsinx }\]
\[\frac{ 1-\sin^2x }{ sinx cosx }\]
\[\frac{ \cos^2x }{ sinx cosx}=\frac{ cosx }{sinx }=cotx\]

Answer 3

@ASAAD123 how did you get from step 1 to step 2 ?

Answer 4

ya were did "ccosx-sin^2cosx" come from?

Answer 5

2) http://openstudy.com/users/asaad123#/updates/515ce537e4b02fd2c0cdc814