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Mathematics 17 Online
OpenStudy (anonymous):

Linear algebra question

OpenStudy (anonymous):

OpenStudy (anonymous):

I can't figure out the right answer >.> .

OpenStudy (anonymous):

this is homework

OpenStudy (anonymous):

I know.

OpenStudy (anonymous):

your a cheater

OpenStudy (anonymous):

The heck? What wrong with asking for help? Troll.

OpenStudy (anonymous):

we do not cheat on this site

OpenStudy (anonymous):

@Preetha

OpenStudy (preetha):

Dido are you allowed to get help on this assignment?

OpenStudy (anonymous):

Yeah. It's collaboration.

OpenStudy (anonymous):

It's not a test or anything. Really!

OpenStudy (anonymous):

but you said to me you know it's your homework

OpenStudy (anonymous):

What's wrong with asking if I don't get how to solve a question?

OpenStudy (anonymous):

I tried using the formula but it doesn't work after taking the norm.

OpenStudy (anonymous):

but don't post your homework up there to get answers

OpenStudy (anonymous):

But I just need an explanation >.> .

OpenStudy (anonymous):

Why is my procedure wrong?

OpenStudy (anonymous):

post like a example are something but not your homework

OpenStudy (anonymous):

You aren't helping the situation.

OpenStudy (anonymous):

what I'm saying don't post your homework post a example not your homework

OpenStudy (anonymous):

I could have lied and said this was an example.

OpenStudy (anonymous):

well i'm sorry for all this

OpenStudy (anonymous):

You are asking questions too. Hypocrite.

OpenStudy (preetha):

Ok, everyone, lets help Dido. He/She says it is not a test - and that he/she is allowed to get help. Lets help. And Dido would you mind accepting 50-c apology graciously?

OpenStudy (anonymous):

yes Preetha

OpenStudy (anonymous):

Yeah sure. He didn't need to get like that though.

OpenStudy (anonymous):

what you need help on @Dido525

OpenStudy (anonymous):

I don't see what I am doing wrong. I use the formula provided and I take the square root. I am not getting the right answer.

OpenStudy (aravindg):

so basically the question asks for inner product and you are given the vectors p and q

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

Well, the distance rather.

OpenStudy (anonymous):

And distance is just norm.

OpenStudy (aravindg):

d represents distance from ?

OpenStudy (anonymous):

I ASSUME P to q. I am not sure about that though.

OpenStudy (dan815):

what is d(p,q) what is the d?

OpenStudy (anonymous):

d meaning distance.

OpenStudy (dan815):

so magnitude of this vector?

OpenStudy (anonymous):

distance between 2 polynomials.

OpenStudy (anonymous):

Doesn't work if I do that.

OpenStudy (dan815):

(p,q) = innet product so d(p,q) = distance of inner product waat?

OpenStudy (anonymous):

d(p,q) is the distance between the two polynomials p and q.

OpenStudy (anonymous):

You could say the norm as well.

OpenStudy (dan815):

oh ok whats the point of that inner product formula then

OpenStudy (anonymous):

That's the thing. I am confused about that.

OpenStudy (anonymous):

If I just used the norm formula I don't get the right answer.

OpenStudy (dan815):

i vaguely remember having to take integrals of innerproduct but i forgot why i did that

OpenStudy (anonymous):

Erm... I don't think that's necessary...

OpenStudy (dan815):

ohh for fourier series stuff

OpenStudy (anonymous):

Lol!!! That's beyond the scope of our text.

OpenStudy (dan815):

i was just wondering that inner product word sounded familiar its stuff u do for fourier series

OpenStudy (anonymous):

How is \(d\) defined here?

OpenStudy (anonymous):

I assume d is distance.

OpenStudy (anonymous):

what formula for distance is being used?

OpenStudy (dan815):

did u try just multiplying em together and entering it

OpenStudy (anonymous):

I am guessing the formula for norm but I am not getting the right answer if I use that.

hartnn (hartnn):

what answer did you get ?

OpenStudy (anonymous):

Remember that \[ \|a\|^2 = <a,a> \]

OpenStudy (anonymous):

Well the correct answer is 3 but I am not really sure how it is that.

hartnn (hartnn):

yeah, i get 3 also.

OpenStudy (anonymous):

The heck? How??

hartnn (hartnn):

d(p,q) = ||(q-p)|| =.... ?

hartnn (hartnn):

first find q-p

OpenStudy (anonymous):

Umm okay.

OpenStudy (anonymous):

OOO!!! I see it!!

OpenStudy (anonymous):

Thank you!!

hartnn (hartnn):

:)

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

Man, I thought my hint would be helpful!

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