Question

To which set of numbers does the number below belong?
-14/11


A. integers

B. irrational numbers

C. natural numbers

D. rational numbers

Answer 1

i knw its not b

Answer 2

Do you know the "definition" of each set?

Answer 3

The first type of number is the first type you ever learned about: the counting, or "natural" numbers:

1, 2, 3, 4, 5, 6, ...

Answer 4

rational number: A real number that can be expressed as the quotient of two integers.

Answer 5

The next type is the "whole" numbers, which are the natural numbers together with zero:

0, 1, 2, 3, 4, 5, 6, ...

Answer 6

Then come the "integers", which are zero, the natural numbers, and the negatives of the naturals:

..., –6, –5, –4, –3, –2, –1, 0, 1, 2, 3, 4, 5, 6, ...

Answer 7

rational numbers

Answer 8

Rational Numbers
Rational numbers have integers AND fractions AND decimals. Now you can see that numbers can belong to more than one classification group. Rational numbers can also have repeating decimals which you will see be written like this: 0.54444444... which simply means it repeats forever, sometimes you will see a line drawn over the decimal place which means it repeats forever, instead of having a ...., the final number will have a line drawn above it.

Answer 9

Irrational Numbers
Irrational numbers don't include integers OR fractions. However, irrational numbers can have a decimal value that continues forever WITHOUT a pattern, unlike the example above. An example of a well known irrational number is pi which as we all know is 3.14 but if we look deeper at it, it is actually 3.14159265358979323846264338327950288419.....and this goes on for somewhere around 5 trillion digits!

Answer 10

Correct $$\frac{-14}{11}$$ belongs to the set of rational numbers.

Answer 11

The rational numbers are numbers where one integer is divided by another (nonzero) integer, so a number is rational if it is a fraction.

Answer 12

The irrational numbers are numbers which cannot be written as a fraction, like pi, e, sqrt(2), the 10th root of 17, etc...