http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s11_qp_11.pdf Question 35
@ameeron you there ?
Yes
Please help
firstly, this is math section and Q 35 belongs to engineering (or physics), so this is wrong place to post it, but since you are new here, i'll help you this time. Do you know Current Division Rule ?
No, i don't
But i know that voltage is equal in a parallel circuit
read the resistive divider section first... http://en.wikipedia.org/wiki/Current_divider
Yes yes, I know this rule
How can i use it here?
ok, so current in 1 ohm branch will be I1 = 5 * (2||5) / (1+ 2||5) got this ?
Not really, please explain further
the resistance of branch parallel to 1 ohm is the parallel combination of 2 ohm and 5 ohm that makes RT in that formula.
What is RT?
\[what is this sign \left| ? \right| ?\]
||
|| means parallel
I know that the total resistance is equal to 10/7 , what should i do after that?
ok, lets go that way, you know total, resistance, you know total current = 5A then the voltage across them will be..... ?
Sorry, disconnection
we need to find the voltage across the 2 ohms resistor only?
voltage across each branch will be equal, as they are in parallel.
True
Then?
what voltage you got ?
10/7 multiply 5, right?
That will be 7.14V
now you have V across 2 ohm, V= 7.14, R=2 find I using ohms law.
3.57A ?
That is none of the choices!
because i think 10/7 is incorrect. R eq = (1/1 +1/2+1/5)^-1 = (17/10)^-1 = 10/17
and not 10/7
10/17*5/2 = 1.47 = 1.5 approx.
got it ?
Thanks alotttttttttt!!!! I had that silly mistake of taking 7 instead of 17!
you rock (:
and you please explain Question 9 too
can you*
please ask that in physics question, i am sure some1 will help you there...
No one wants to help!
i think that because the options are not correct ? if the moving body sticks to stationary body, there will be no velocity and hence no K,E (K.E=0), but thats not a choice. Thats why even i was reluctant to answer that at first. But even i am not sure about this, i may be wrong...
When they say stick, they mean that they stick and move off together with the same velocity
oh, well..then i am not sure on how to find those....
Thank you anyways.. what's ur age btw?
Was just wondering
hmm.. i am 23
Engineer?
yes, completed graduation, and now pursuing post graduation.
if we are done with the question, can you please close the question ? if you want to ask me anything else, message me.
Sure
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