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Chemistry 26 Online
OpenStudy (anonymous):

Determine whether the following combinations of atoms will form monatomic ions or polyatomic ions: a. Oxygen (O) & Carbon b. Sodium (Na) & Bromine (Br) c. Oxygen (O) & Chlorine (Cl) d. Cesium (Cs) & Chlorine (Cl) e. Oxygen (O) & Nitrogen (N) f. Potassium (K) & Iodine (I) g. Carbon (C) & Nitrogen (N) h. Rubidium (Rb) & Fluorine (F)

OpenStudy (abb0t):

Do you know the defiition of a monoatom and polyatomic ion?

OpenStudy (anonymous):

okay, i thought polyatomic had 1 or more atoms and monatomic had 1. That's why i'm confused cuz ur adding 2 together.

OpenStudy (chmvijay):

not 1 or more its always more than one for polyatomic

OpenStudy (anonymous):

ya thats what i meant sorry

OpenStudy (anonymous):

2 or more accidently hit 1

OpenStudy (abb0t):

Yes. 2+ for polyatomics

OpenStudy (anonymous):

but if you add 2 together it has more than 1

OpenStudy (chmvijay):

what more than 1 :)

OpenStudy (anonymous):

you have C and O makes Carbon Monoxide but since it has 2 C = 1 O= 1 1+1=2 its polyatomic? then they should all be polyatomic.

OpenStudy (chmvijay):

what u said is right about CO but it can also be CO2 right i am also getting confused with this

OpenStudy (anonymous):

yes it would still be polyatomic though right? how would any be monatomic?

OpenStudy (chmvijay):

h. Rubidium (Rb) & Fluorine (F) f. Potassium (K) & Iodine (I) d. Cesium (Cs) & Chlorine (Cl b. Sodium (Na) & Bromine (Br) are mono atomic while others are polyatomic i think

OpenStudy (anonymous):

how are they monatomic?

OpenStudy (chmvijay):

A can form CO2 C can form OCl2 e can form NO2 g can form CN3 like that

OpenStudy (anonymous):

oh ok it makes sense now. thanks

OpenStudy (chmvijay):

see in their combination will give rise to only one atom for Ex NaBR n othing more than that combination is possible but in other case its not like that u can have different combination to have polyatomic molecules

OpenStudy (chmvijay):

just this is my views

OpenStudy (anonymous):

okay:) thanks

OpenStudy (anonymous):

ha thanks:)

OpenStudy (chmvijay):

:)

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