Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

The graph below displays how many pieces of candy Timmy and his five friends each received last Halloween. Within how many standard deviations of the mean do the values fall?

OpenStudy (anonymous):

OpenStudy (anonymous):

helpppppppppppppppppppp!~!!!!!!!!!!!!!!

OpenStudy (jpsmarinho):

@KeemoD143 , I'm not sure to solve this problem, but let's try together to solve?

OpenStudy (jpsmarinho):

The mean equal to (16+19+25+32+38+40)/6, right?

OpenStudy (anonymous):

hpw do we start ////?

OpenStudy (jpsmarinho):

Right?

OpenStudy (anonymous):

pellet conffusing

OpenStudy (jpsmarinho):

What's the mean of 10 and 10? It's 10 because (10+10)/2 = 10 Of 10 and 5? (10+5)/2 = 7,5 Of 10 , 10 and 5? (10+10+5)/3 = 8,33 So, mean is a formula like this: (x1+x2+x3+...+xn)/n

OpenStudy (jpsmarinho):

In the graph you have the values 16,19,25,32,38 and 40 So (the sum of the values)/(quantity of values) = mean of values

OpenStudy (jpsmarinho):

@KeemoD143 you closed the question, why?

OpenStudy (anonymous):

accident

OpenStudy (jpsmarinho):

But you understand this?

OpenStudy (jpsmarinho):

What I wrote?

OpenStudy (anonymous):

checking it now wouldnt the answer be out of 1 or 4 ??

OpenStudy (jpsmarinho):

my result is approximately 10...

OpenStudy (anonymous):

10 isnt an answer

OpenStudy (jpsmarinho):

standard deviation (I`m not sure if you know) is how much dispersion from the mean. ( How far the values is of the mean). to find the standard deviation, calculate the mean ( I wroted above) and then subtract each value from the mean and square the result of each subtraction: mean = (16+19+25+32+38+40)/6 = 28.33 (16 - 28.33)^2 (19 - 28.33)^2 . . . then, sum all the values above: (16 - 28.33)^2 + (19 - 28.33)^2 and then divide this sum for (number of elements -1), in this case, 5 ( 6-5) and then square root this value ^^ its confusing, right?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!