Question

A vector of magnitude 20sqrt6 sirected along the bidector of the angle of the angle between a=7i - 4j -4k and b=-21 - j +2k? @shubhamsrg

Answer 1

Maine kya kiya c=20sqrt6 (a/|a| + b/|b|). Aise hi nikalte hain na bisector? But isse answer galat aa rha hai. :/
Denominator me jo 9 aayega (a/|a| + b/|b|), isse, uski jagah pta nhi 4 de rkha hai.

Answer 2

aise hi hoga :')

Answer 3

Vo 4 kahan se aayega?

Answer 4

nahi hoga koi 4,
9 and 3 hoga :')

Answer 5

Mai fir se check krta hun ruko.
Ek baar solve kar, dekh aa rha hai 5/3( i -7j +2k) ?

Answer 6

ab solve wagerah nahi karunga, aalas aa raha hai :P
tareeka sahi hai, :)

Answer 7

Wtf. Please?

Answer 8

kartik me faad dala! :D

Answer 9

ne*

Answer 10

Are yr plz? :/

Answer 11

a=7i - 4j -4k and b=-21 - j +2k

7/9 -2/3 i - 4/9 -1/3 j -4/9 + 2/3 k

i/9 -7j/9 +2k/9
ye hoga na ?

Answer 12

Haan. Ye aa gya. Ab?

Answer 13

*20sqrt6

Answer 14

Bas?

Answer 15

ha sahyd :|

Answer 16

5/3( i -7j +2k) <-- Answer ?

Answer 17

:|

Answer 18

Solve krke btao plz. :/

Answer 19

20sqrt6 se ye kaise aa jayega ?
i-7j +2k to aa raha hai

Answer 20

Aur ek aur cheez book me kya kri hui hai ki i-j+2k ka bhi unit vector banaya hua hai. sahi baat hai. but usse bhi answer nhi aa rha.

Answer 21

@AravindG

Answer 22

Book me ye likha hai..
Let a,b be the position vectors of A and B respectively. Then the bisecotr of angleAOB divivides AB in the ratio OA:OB=9:3 or 3:1. Therefore the vector lying along the bisector is
[ 3(-21 - j +2k) + (7i - 4j -4k ) ] / 3+1
Ye kya kiya hai? :/

Answer 23

nahi maalum :'(

Answer 24

Koi na. :'(

Answer 25

4 runs last ball!
dafaq! :O