Question

@AriPotta

Answer 1

is the second one C?

Answer 2

Question 7: A \[(8+\sqrt{2})(4-3\sqrt{2}) \rightarrow 32 -24\sqrt{2}+4\sqrt{2}-3\sqrt{2}\sqrt{2}\]\[32-20\sqrt{2}-3(2) \rightarrow 32-6-20\sqrt{2} \rightarrow 26-20\sqrt{2}\]

Answer 3

thanks guys!

Answer 4

and with the first one, just multiply the two fractions. 2/3 x 4/5 = 8/15

Answer 5

what about the #6 ?

Answer 6

Which of the following is a solution to √x-4+9=6

Answer 7

x = 17

x = 15

x = 5

x = 3

Answer 8

@AriPotta

Answer 9

is that sqrt(x - 4) + 9 = 6?

Answer 10

x = –3

x = –7

x = 1

x = 13

I put the wrong answer choices

Answer 11

yes

Answer 12

ok, so subtract 9 first

Answer 13

√x-4-3 ?

Answer 14

sqrt(x - 4) + 9 = 6
sqrt(x - 4) = -3

then square it
[sqrt(x - 4)]^2 = -3^2
x - 4 = 9

add 4
x = 13

Answer 15

i have one more. I gonna see if I can do it

Answer 16

6√x+1=24

Answer 17

I got it wrong.
i got 88

Answer 18

x = 17

x = 15

x = 5

x = 3

Answer 19

divide by 6
6sqrt(x + 1) = 24
sqrt(x + 1) = 4

square it
[sqrt(x + 1)]^2 = 4^2
x + 1 = 16

subtract 1
x + 1 = 16
x = 15