Question

Help with high school chemistry 1. This is about calorimetry...Please Help!!

Answer 1

wts d question

Answer 2

Calculate the energy change (q) of the surroundings (water) using the enthalpy equation

qwater = m × c × ΔT.

We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL.

The water has absorbed the heat of the metal. So, qwater = qmetal

Answer 3

give the data man

Answer 4

Part 1:
Known Metal: Alluminum
Measured mass of metal 27.776 grams
Distilled water measurement 25 mL
Distilled water temperature 25.2 degrees Celsius
Temperature of metal 100.8 degrees Celsius
Temperature of mixture 38.9 degrees Celsius

Answer 5

specific heat capacity of metal???

Answer 6

The other part says this:
Using the formula qmetal = m × c × ΔT, calculate the specific heat of the metal. Use the data from your experiment for the metal in your calculation

Answer 7

ok wait i'll try it in 2 mins

Answer 8

u just got2 equate the heat gained by water and heat lost by metal........The calculations are quite tough due to many decimal places......Try it out urself first i hv worked the answer

Answer 9

Im pretty confused. What should i calculate first?

Answer 10

its ur wish..........just read the data carefully dts it

Answer 11

What im asking is, is there an equation I should be following?

Answer 12

q=energy gained or lost in joules
m=27.776
c=specific heat capacity of the sample. [j/(degrees c*grams)]
Delta T=the change in temperature when it gains or loses the energy.

Answer 13

yes just use this and put values in qwater=qmetal

Answer 14

Im having trouble with [j/(degrees c*grams)] and delta t

Answer 15

y? take care of units

Answer 16

Am i using the distilled water temperature or the metal temperature?

Answer 17

T(initial) for water is distilled one T(final) for water is the mixture temp.
T(initial) for metal is metal temp. and T(final) for metal is mixture temp.
Gotta go bbye

Answer 18

27.776*4.18*(25.2-38.9)

Answer 19

=1,590.620416

Answer 20

\(q_{water}=mc \Delta T\) start by finding the mass using the known density relationship of water \(Density = \frac{ mass }{ volume }\). Next you can find the relative change in temperature: \(\Delta T = T_{mix}-T_{water}\). Now you have everything to find energy, q.
Now, \(q_{water} = - q_{metal}\) so the energy of water is actually negative.
Follow the same process for aluminum, get the mass, find the change in temp (∆T). Find, c (specific heat)...and same process for part B.