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Simplify the fraction. Question attached.
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\[x(x ^{2}+x+1)/x+1\] is your answer
how did get to that answer?
\[\Large\dfrac{x^{n+3}-x^n}{x^{n+2}-x^n} = \dfrac{x^n(x^{3}-1)}{x^n(x^{2}-1)}\]\[\Large~~~~~~~~~~~~~~~~~=\dfrac{x^3-1}{x^2 -1} = \dfrac{(x-1)(x^2+x+1)}{(x-1)(x+1)} = \boxed{\dfrac{x^2+x+1}{x+1}}\]
Is this clear? @Softballgirl372015
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yes this very clear. Thank you so much!
You're welcome.
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