Question

Find the domain of the function f( x)= square root x-2+3

Answer 1

hang on

Answer 2

Well, whatever is under the root must be >=0. So solve for 0, and that gives you what it must be >= to.

Answer 3

is it square root x-2+3 or just x-2

Answer 4

@pvs285 Good point.

Answer 5

@jim_thompson5910

Answer 6

katlin95 we need that to solve

Answer 7

square root x-2+3

Answer 8

is the square root over all of those numbers

Answer 9

or just over x-2

Answer 10

yep square root over the whole problem

Answer 11

x >= -1

Answer 12

http://www.mathway.com/math_image.aspx?p=xSMB03SMB01-1?p=47?p=22

Answer 13

the number is in the top corner of that web sight

Answer 14

If the equation is

\[\Large f(x) = \sqrt{x-2}+3\]

then you solve

\[\Large x-2 \ge 0\]

------------------------------

If the equation is

\[\Large f(x) = \sqrt{x-2+3}\]

then you solve

\[\Large x-2+3 \ge 0\]

Answer 15

I know its supposed to be x>-1 but heres my multiple choice that it says

Answer 16

A. x≥2
B. x<-2
C. x>2
D. x≥2

Answer 17

solve

\[\Large x-2 \ge 0\]

Answer 18

its x >= 2

Answer 19

D is supposed to have a -2 sorry lol

Answer 20

so its A.