Find the odds in favor of getting at least two tails when five fair coins are flipped.
Okaii lets start: Odds in favor = \[\frac{ want }{ dontwant }\]
alright, got that part
@jim_thompson5910
Do you have a thought on this? Any ideas of what it would be, first?
Me? Not really, I thought it was something out of 32 just because 32 is the number of times it's flipped, but that's about as far as I got
it should be want ------ total
so 32, would be the second number, but I'm not sure on the first number still
Odds is favor, @jim_thompson5910 ?
yeah odds in favor are what you want over total
What I thought is that: Odds in Favor = want/don't want Odds Against = don't want/want
okay so how do I find what I want?
yeah @jim_thompson5910 "Odds in Favour/Favor of an Event is the ratio of "Number of Favorable Choices (Successes)" to "Number of Unfavourable Choices (Failures)"."
And "Odds against an Event is the ratio of "Number of UnFavourable Choices (Failures)" to "Number of Favorable Choices (Successes)". "
There are 32 ways to flip 5 coins There is 1 way to flip all heads: HHHHH ------------------------------------------------------- There are 5 ways to flip 4 heads and 1 tail: HHHHT HHHTH HHTHH HTHHH THHHH
So there are 6 ways to flip either 0 tails or 1 tail
So the odds in favor are 26: 6 using the definition some_someone wrote out
you can reduce that to get 13 : 3
Got it, Thank you!!!
Join our real-time social learning platform and learn together with your friends!