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Mathematics 20 Online
OpenStudy (anonymous):

Find the odds in favor of getting at least two tails when five fair coins are flipped.

OpenStudy (anonymous):

Okaii lets start: Odds in favor = \[\frac{ want }{ dontwant }\]

OpenStudy (anonymous):

alright, got that part

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

Do you have a thought on this? Any ideas of what it would be, first?

OpenStudy (anonymous):

Me? Not really, I thought it was something out of 32 just because 32 is the number of times it's flipped, but that's about as far as I got

jimthompson5910 (jim_thompson5910):

it should be want ------ total

OpenStudy (anonymous):

so 32, would be the second number, but I'm not sure on the first number still

OpenStudy (anonymous):

Odds is favor, @jim_thompson5910 ?

jimthompson5910 (jim_thompson5910):

yeah odds in favor are what you want over total

OpenStudy (anonymous):

What I thought is that: Odds in Favor = want/don't want Odds Against = don't want/want

OpenStudy (anonymous):

okay so how do I find what I want?

OpenStudy (anonymous):

yeah @jim_thompson5910 "Odds in Favour/Favor of an Event is the ratio of "Number of Favorable Choices (Successes)" to "Number of Unfavourable Choices (Failures)"."

OpenStudy (anonymous):

And "Odds against an Event is the ratio of "Number of UnFavourable Choices (Failures)" to "Number of Favorable Choices (Successes)". "

jimthompson5910 (jim_thompson5910):

There are 32 ways to flip 5 coins There is 1 way to flip all heads: HHHHH ------------------------------------------------------- There are 5 ways to flip 4 heads and 1 tail: HHHHT HHHTH HHTHH HTHHH THHHH

jimthompson5910 (jim_thompson5910):

So there are 6 ways to flip either 0 tails or 1 tail

jimthompson5910 (jim_thompson5910):

So the odds in favor are 26: 6 using the definition some_someone wrote out

jimthompson5910 (jim_thompson5910):

you can reduce that to get 13 : 3

OpenStudy (anonymous):

Got it, Thank you!!!

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