I've never seen a5 before!!!!!
What is the 7th term of the geometric sequence where a1 = -5 and a5 = -1,280? (3 points)
Answer
5,120
-5,120
20,480
-20,480
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hartnn (hartnn):
a5 means the 5th term.
OpenStudy (anonymous):
oh:)
hartnn (hartnn):
first find r=common ratio, using the formula,
\(\huge a_n=a_1r^{n-1}\)
n=5, a1=-5,a5=-1280
OpenStudy (anonymous):
okay:)
OpenStudy (anonymous):
what would i plug in for r into the equation?
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hartnn (hartnn):
you need to find 'r' from that equation, thats the only unknown variable.
OpenStudy (anonymous):
n = 7 I thought
hartnn (hartnn):
remember that you have the value of a5.
n will be 7 when you'll find the 7th term.
now you are finding r, using 5th term, so n= 5 first
OpenStudy (anonymous):
oh alright
OpenStudy (anonymous):
-5 x r ^(5-1)
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OpenStudy (anonymous):
-5^4?
hartnn (hartnn):
no....
a5=-1280
so, -1280 = -5 r^4
try to isolate and find r from here.
hartnn (hartnn):
first you can divide by -5 on both sides.
hartnn (hartnn):
can you find r ?
OpenStudy (anonymous):
let me try
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OpenStudy (anonymous):
-1280/5?
hartnn (hartnn):
r^4 = -1280/ -5 =.... ?
OpenStudy (anonymous):
256
hartnn (hartnn):
yes, r^4 = 256, so r=.... ?
OpenStudy (anonymous):
4294967296
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hartnn (hartnn):
:O
r^4 = 265
\(\large r = \sqrt[4]{256}=...\)
don't do 256^4
OpenStudy (anonymous):
Oh really?? my error one sec
OpenStudy (anonymous):
4 sqrt 256
= 4sqrt of (4^4)
= 4
OpenStudy (anonymous):
not quite sure if that's correct
hartnn (hartnn):
yes, r= 4 is correct.
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OpenStudy (anonymous):
oh okay good
OpenStudy (anonymous):
ill plug it in
hartnn (hartnn):
now you need 7th term
now take n = 7
r= 4
a1 =-5 as always.
plug these in
\[\huge a_n=a_1r^{n-1}\]
OpenStudy (anonymous):
-5 x 4^ (5-1)
OpenStudy (anonymous):
oh right!!! n= 7 this time
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hartnn (hartnn):
yes, because you are finding 7th term
OpenStudy (anonymous):
-5 x 4= -20
i don't know how to plug the whole to the power of "(7-1)"
hartnn (hartnn):
again!
don't do -5*4 first!!
^ has greater priority,
so do
4^{7-1} = 4^6 first
then multiply by 5
OpenStudy (anonymous):
4^(7-1) = 4096
hartnn (hartnn):
yes, 4096*(-5)= ?
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