Question

If sin(...)

Answer 1

\[\LARGE \sin(\sin^{-1}\frac{1}{5}+\cos^{-1}x)=1,~find~the~value~of~x\]

Answer 2

1/5

Answer 3

thisi s a trick

Answer 4

HOW :O

Answer 5

#genius!

Answer 6

lol\[
\sin^{-1}{1\over5}+\left({\pi\over2}-\sin^{-1}(x)\right)={\pi\over2}
\]

Answer 7

:/ lol

Answer 8

I see what you did there,but how did you simplify it?

Answer 9

\[
\sin^{-1}{1\over5}+\left(\cancel{\pi\over2}-\sin^{-1}(x)\right)=\cancel{\pi\over2}
\]

Answer 10

oh great :D

Answer 11

so
\[\large \sin^{-1}x=\frac{1}{5}\]
same for cos?

Answer 12

what!
\[\sin^{-1}x=\sin^{-1}{1\over5}\implies x={1\over 5}\]

Answer 13

:/ silly me :P