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If it takes 30 mL of a 0.25M NaOH solution to neutralize 80 mL of a HCl solution, what is the Molarity of the HCl solution?
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what kind of reaction is this?
It's a neutralization reaction. I think to solve it you need to use the M(a)V(a) = M(b)V(b) equation?
not quite, that formula is for dilutions. you're basically finding the moles present in 30 mL of 0.25 M NaOH, then since you know they react in a 1-to-1 ratio (in terms of moles), find the molarity of the acid. the only formula you have to use is Molarity=moles/L of solution
Thank you so much!
no problem !
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