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Mathematics 24 Online
OpenStudy (anonymous):

Write the expression as a single logarithm 3log(b)q+6log(b)v A. log(b)(q^3v^6) B. (3+6)log(b)(q+v) C. log(b)(qv^3+^6) D. log(b)(q^3+v^6)

OpenStudy (kropot72):

\[3\log_{b} q+6\log_{b} v\] The first step is to rearrange each of the terms using the following rule: \[a \log_{b} c=\log_{b} c ^{a}\] Can you do that?

OpenStudy (anonymous):

no

OpenStudy (kropot72):

Lets do the first term using the rule: \[a \log_{b} c=\log_{b} c ^{a}\] \[3\log_{b} q\] You take the coefficient of the term, which is 3, and raise q to the power of 3: \[3\log_{b} q=\log_{b} q ^{3}\] Can you follow this procedure for the second term: \[6\log_{b} v=?\]

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