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Mathematics 17 Online
OpenStudy (anonymous):

prove that

OpenStudy (anonymous):

OpenStudy (anonymous):

You mean prove the golden ratio is equal to... well, something?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Well, you want to prove that the golden ratio \[\huge \varphi = \frac{1+\sqrt5}{2}\]?

OpenStudy (anonymous):

i don't know in book, its only written what i have attached

OpenStudy (anonymous):

i think its impossible because there is no written golden rule for a question

OpenStudy (anonymous):

Well, you can't be expected to prove that \[\huge \frac{a+b}{a}=\frac{a}b\]outright... there are only so many values of a and b which would make this equation false...

OpenStudy (anonymous):

hmm yes peterpan u r right

OpenStudy (anonymous):

@Mertsj

OpenStudy (mertsj):

There is something missing in your problem. Perhaps a diagram? Because what you have posted is not, in general, true. Therefore it cannot be proven to be true unless there are some other conditions.

OpenStudy (mertsj):

I suspect you were given the golden rectangle and told to prove, using similar figures, that your proportion is true.

OpenStudy (mertsj):

http://www.jimloy.com/geometry/golden.htm

OpenStudy (mertsj):

http://en.wikipedia.org/wiki/Golden_rectangle

OpenStudy (mertsj):

http://wn.com/golden_rectangle Some videos that might help.

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