Question

lim x-> 1 (x^2+2x-3)/(2x^2-5x+3)
can someone tel lme how to solve this?

Answer 1

\[\lim_{x\to1}\frac{x^2+2x-3}{2x^2-5x+3}
\]
when you apply the limit i.e., replace "x" with "1", you get "division by zero" .
So, there must be a (x-a) factor in the denominator. So,first factor out the numerator and the denominator.

Answer 2

ok

Answer 3

you can use the equation editor below to enter your steps

Answer 4

thank you so much..so the limit is -4 ?

Answer 5

yep

Answer 6

you wouldnt believe the misdirection I was given by a paid tutor!!!!!!!

Answer 7

:)
sorry to hear that!!

Answer 8

never again. You guys rock!!!!

Answer 9

you too. enjoy math and open education