A package contains 6 candy canes, 4 of which are cracked. If 2 are selected, find the probability of getting exactly one cracked candy cane.

Question

anonymous · Answer

2 out of 6 or 
1 out of 3

anonymous · Answer

are you selecting them at the same time, or one wait then pick the other one?

anonymous · Answer

i think that this is a binomial probability

anonymous · Answer

it doesn't matter. The probabilty will still be the same.

anonymous · Answer

oh, this is actually not that hard.  when problems say at least _____.  its code for 1-P(not getting any of ______)

so when it says probability of getting exactly one cracked candy cane.

it is actually saying find the 1-P(not getting any cracked candy canes)

anonymous · Answer

do you know what the binomial distribution is?

anonymous · Answer

I think above's way is easier but you can also think by this way . picking cracked one's probabilty is 2/3(=4/6) and picking normal one's is 1/3 .  so you have to multiply them . You can switch their position like (cracked one .normal one) (normal one, cracked one) so you also have to multiply 2  so the answer is 4/9