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Probability
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A package contains 16 candy canes, 6 of which are cracked. If 3 are selected, find the probability of getting exactly two cracked candy canes.
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The probability can be taken here by Combinations. I believe algebra?
(6 2)*(10 1)/(16 3)
To randomly select 3 out of 16, of which 2 are crached, you need 6C2*10C1=6!/(4!2!) * 10=Cases in which you've selected 2 cracked candy.
The next part is the total number of cases. Which is 16C3=(16*15*14)/(3*2)
You divide the former expression by latter. I hope it helps.
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