Question

Algebra 2 Help! Question attached.

Answer 1

Where is the question?? :P

Answer 2

\[2^{x}-3^{x}=0\]

Answer 3

solve for x

Answer 4

Do you know about logarithms?

Answer 5

no i do not. thats in the next few sections.

Answer 6

Oh :S May I ask what grade you are in if you don't mind.

Answer 7

i am in 10th grade taking honors algebra 2.

Answer 8

what grade are you in?

Answer 9

Oh I'm in grade 12.

Answer 10

That explains it. But I'm sure your teacher should teach you about logarithms.

Answer 11

yea i will learn about them this week coming up, but do you know how to solve this without using logs?

Answer 12

Well the only thing that comes to mind in x=0

Answer 13

okay thats the right answer according to my textbook, but how do i get to that answer? is it because the bases are not equal?

Answer 14

That's using common sense. In order for \[2^{x} -3^{x}=0\]
Then \[2^{x} = 3^{x}\]
and the only way that can be true is if x =0 because when x=0 the left side equals 1 and the right side equals 1 and plugging that back into the equation
\[2^{x} -3^{x}=0\]
\[1 -1=0\]
Therefore left side equals right side.

Does that explain it?

Answer 15

yea it does!! thank you so much!! :)

Answer 16

You're welcome :) Have fun :)