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I have the answer can someone please check me Where does f(x)=e^x-kx have a relative minimum?
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"relative" so, just the first derivative and second derivatives like before.
sort of I got x=lnk
sort of yes.
good. now, the second derivative would be?
\[f''(x)=?\]
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no I mean that is the answer for the problem
yes.
\[f'(x)=e^x-k=0\\\implies e^x=k\implies x=\ln(k)\]
ok thanks
only one critical point... this is true IF and ONLY if.. k>0
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Im confused so is my answer right or not
yes it is.
ok thanks
but.. for reference, "ln" is not defined for numbers "0 or less" so, "k" cannot be "0 or negative"
that piece of information must be provided with the question.
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well I wrotw the question down exactly
so, write what I said on your answer and impress your prof. ;)
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